+ 6
How is this even possible?
public int toDecimal(String bin){ int x=0,dec=0; for(x=0;x<=bin.length()-1;x++){ dec+=(2*((int)bin.charAt(x))); } return dec; } the above code is my binary to decimal converter, however, when I give input 10 it gives output 194, shouldn't it give 2?
5 Antworten
+ 16
The conversion of char to int gives ASCII value.
49*2 + 48*2
= 194
+ 14
Sure. Apparently, your conversion logic is not correct. For example, 10110's equivalent decimal is 22, but multiplying each character by 2 will provide 6.
The logic should be:
10110
= 1*2^4 + 0*2^3 + 1*2^2 + 1*2^1 + 0*2^0 (^ means power here)
= 1*16 + 0*8 + 1*4 + 1*2 + 0*1
= 22
So, here is the corrected code:
public static int toDecimal(String bin){
int x=0, y,dec=0;
for(x=0, y=bin.length()-1;x<=bin.length()-1;x++, y--){
dec+= (bin.charAt(x)-'0')*Math.pow(2, y);
}
return dec;
}
// subtracting ASCII value of '0' will convert the char to int
+ 6
thanks
+ 4
ok
+ 4
can you help me here