No numerals test case 3 passed

Question

https://www.sololearn.com/coach/64?ref=app

Answer 1

Vishal

If there is 10 then it's doesn't mean it is one zero. It should be "ten". So first you have to replace 10 with "ten"

Answer 2

#include <stdio.h>
#include <string.h>

int main() {
char arr[100];
fgets(arr, sizeof(arr), stdin);
int s= strlen(arr);

for(int i=0; i< s; i++){

if(arr[i] >= 48 && arr[i]<=57){
goto num;
}
printf ("%c", arr[i]);

num:
if(arr[i] >= 48 && arr[i]<=57){

switch (arr[i])

{
case '0':
printf ("zero");
break;
case '1':
printf ("one");
break;
case '2':
printf ("two");
break;
case '3':
printf ("three");
break;
case '4':
printf ("four");
break;
case '5':
printf ("five");
break;

case '6':
printf ("six");
break;
case '7':
printf ("seven");
break;

case '8':

printf ("eight");
break;

Answer 3

case '8':

printf ("eight");
break;
case '9':
printf ("nine");
break;

case '10':

printf ("ten");
break;

}

}
}

return 0;
}

Answer 4

Test case 3 not passed

Answer 5

YUGRAJ

STILL NOT GETTING

if(arr[i] >= 48 && arr[i]<=57){
goto num;
}
printf ("%c", arr[i]);

num:

if(arr[i] >= 48 && arr[i]<=57){

if(arr[i] == '1' && arr[i+1]== '0'){
printf ("ten");
}

switch (arr[i])

{
case '0':
printf ("zero");
break;
case '1':
printf ("one");

Answer 6

Yeah right now just put i++; and continue after printing ten

Answer 7

YUGRAJ

BUDDY, I have tried it but it didn't work out also changed position sometimes of the statement but nothing happened.

Answer 8

For 10 you have to do two things it should be above all cases and second you need to check two characters so i recommend use if statement before switch and check if current is 1 and next is 0 if so then put ten in answer and increase i one time extra and then continue