Trying to solve skipping 13 in JavaScript

Question

Many tall buildings, including hotels, skip the number 13 when numbering floors -- often going from floor 12 to floor 14. It is thought that the number 13 is unlucky.
Write a program that will number 15 rooms starting from 1, skipping the number 13. Output to the console each room number in separate line.

Answer 1

var countOfRooms = 15;
// Your code here
for (i=1;i<=16;i++){
if(i==13){
continue
}
console.log(i)
}

This worked for me ✌

Answer 2

Yaroslav Vernigora thanks

Answer 3

I think this is the correct way. Try this.

for (i=1; i<=countOfRooms+1; i++){
if(i==13) {
continue;
}
console.log(i);
}

Answer 4

Hi! For better help for you, Please, show us your code attempt! Thx!

Answer 5

var countOfRooms = 15;
// Your code here
for (i=1; i<=15; i++){
if (i==13){
comtinue;
}
document.write(i+"<br/>");
}

Answer 6

easy as heck, just print ALL OF THEM and skip 13th number! AND YOUR TEACHER WILL APPRECIATE IT!

joke aside. attempt it yourself.
edit: Simisola Osinowo oh bruh, you misspelled continue aand you didn't used countOfRooms variable in the for loop.

Answer 7

comtinue -> continue

Answer 8

Now it's saying document not defined

Answer 9

Instead of "document.write" -> insert "console.log"

Answer 10

Done that
var countOfRooms = 15;
// Your code here
for (i=1; i<=15; i++){
if (i==13){
continue;
}
console.log(i);
}

But now it does not print 16

Answer 11

so you have only 15 rooms. at the very beginning, the variable is assigned the value 15

Answer 12

Simisola Osinowo var I is 1 instead of 0

Answer 13

This solution works for me for any number of rooms (I tried to make it reusable)

var countOfRooms = 15;
// Your code here
if(countOfRooms >= 13){
for(var i = 1; i <= countOfRooms + 1; i++){
if(i == 13){
continue;
}
else{
console.log(i)
}
}
}
else{
for(var i = 1; i <= countOfRooms; i++){
console.log(i);
}
}

----------------------------------------------------------------------------------------------------------
Otherwise for this question specifically:

var countOfRooms = 15;
// Your code here
for(var i = 1; i <= countOfRooms + 1; i++){
if(i == 13){
continue;
}
else{
console.log(i);
}
}

edit: added reusable method and easier readability

Answer 14

Tijanihabeeb it needs to be 1 otherwise you'll end up printing a room number of '0'

If you want it to make the loop more reusable for any number of rooms, you'll need to increase the original var

For example:
for (n = 1; n <= countOfRooms; n++) {
if (n == 13) {
countOfRooms++
continue;
}
console.log(n);
}

Answer 15

var countOfRooms = 15;
// Your code here
for (i=1;i<=16;i++){
if(i==13){
continue
}
console.log(i)
}
//I hope, This will helful for the beginner .

Answer 16

var countOfRooms = 15;
// Your code here
for (let countOfRooms=1; countOfRooms<17; countOfRooms++) {

if(countOfRooms == 13) {
continue;
}

console.log(countOfRooms);
}

This worked for me.