How to check using regular expression that atleast two different character from [ . ] is present in my string ?

Question

Suppose I want to check that my string contains atleast two different character from following : [@,#,&,+,*,?] .
Which regex is going to help me here ?

I tried this :

if(s.matches(".*[@#&+*?].*[@#&+*?].*") )
return true ;

, but I knew it will fail for string like "abc@@" as it contains only single special character from my list repeated twice.
I can solve this but the regex will be really long and inefficient, is there a simple way other than this :

if(s.matches(".*@+.*[#&+*?]+.*") ||
s.matches(".*#+.*[@&+*?]+.*") ||
s.matches(".*&+.*[#@+*?]+.*") ||
s.matches(".*\\++.*[#&@*?]+.*") ||
s.matches(".*\\*+.*[#&+@?]+.*") ||
s.matches(".*\\?+.*[#&+*@]+.*") )
return true ;

Answer 1

you can test against only one regex by doing the OR operations inside it:

if (s.matches(".*(@.*[#&+*?]|#.*[@&+*?]|&.*[@#+*?]|\\+.*[@#&*?]|\\*.*[@#&+?]|\\?.*[@#&+*]).*")) return true;

parenthesis are here to spare some char and increase efficiency...

also, suggestion of Akshay Harshora could improve efficiency if you're doing a lot of check with the same pattern ^^

Answer 2

as far as I know, there's no shorter way... but it would increase efficiency compared to your code (and it's shorter), where there are many regex to test ^^

Answer 3

visph , Yes I know that just forgot to implement it, but is there a shorter way

Answer 4

Akshay Harshora , elaborate please

Answer 5

visph , Okay and Thanks for the help