How do I compare a character with ASCII value in C?

Question

#include <stdio.h>
#include <stdlib.h>
#include<string.h>

int main()
{
char ch='A';
int no=97;
if(no==ch) //I know there is other way of doing this but I have no idea
{
printf("This is alphabet %c",ch);
//It is will not be executed

}
return 0;

Answer 1

The ASCII value of the character 'A' is 65, not 97 ('a'), which is why your comparison fails. You can review a ASCII table, e.g. here:

https://www.rapidtables.com/code/text/ascii-table.html

Answer 2

#include <stdio.h>

int main()
{
char ch='a';
int no=97;
int a = (int)ch;
if(a==no)
{
printf("This is alphabet %c",ch);
}
return 0;
}

Use type casting concept.