A program that takes an array of length n and sorts it. And because we use a template, the array can be of any type

Question

A program that takes an array of length n and sorts it. And because we use a template, the array can be of any type.......please help..please

Answer 1

‎زهرا درویشی‎
The error message says it
"couldn't deduce type parameter 't'"

You are not passing any type parameter to the Arraye() function. You need to do
Arraye<type-of-aray>(n)
There is also no point in having 'n' as an argument to the function

Also, you are clearly not sorting the array you are taking as input.

Answer 2

Please directly mail to [e-mail]
They have a free 7/24 service with 10 specialists happy to deliver code within 15 minutes.

Answer 3

You didn't seriously sent an email🤨🤨🤨

friend....at least we want to see some effort.
we will help but not do for you.

Answer 4

Ohhh🤔
So your last chance is showing own effort.

Answer 5

#include <iostream>
using namespace std;

template <class t>
void Arraye(int n)
{

cin>>n;

t b[n];

for(int i=0 ;i<n ;i++)
cin>>b[i];

for (int j=0 ;j<n ;j++)
cout<<b[j];

}

int main()
{

int n;

Arraye(n);

return 0;
}

Answer 6

That's all that came to my mind, but it gives an error

Answer 7

thanks a lot

Answer 8

You can use sort(arr,arr+n), be aware of that it's complexity is O(nlogn).

Answer 9

Can you enter the code, please .. please .. I did not find it

Answer 10

Believe me, I sent but wrote the email address was not found

Answer 11

in main you should specify what kind of array you're using

Arraye<int>(n);

Answer 12

‎زهرا درویشی‎ Hi , hope you are fine 👍🌺 Frogged was actually joking ... there is no email address like that , I think he meant you should put some effort ...