Why output is 4 in both case?

Question

I though evaluation inside printf function works right-to-left, according to this in CASE-1 output 4 is Okay, but in CASE-2 based on right-to-left it should give 3 but it giving 4! Why? Please help!

CASE - 1
int main()
{
int a = 1, b = 1, d = 1;
printf("%d", a + ++a); // Result = 4
}

CASE -2
int main()
{
int a = 1, b = 1, d = 1;
printf("%d", ++a + a); // Result = 4
}

Answer 1

https://www.sololearn.com/Discuss/1879466/?ref=app