Explain how Output comes out to be 6 ?

Question

#include <stdio.h>

int main() {

int i = 3;
if(!i)
i++;
i++;
if (i==3)
i += 2;
i += 2;
printf("%d",i);
return 0;
}

Answer 1

//read comments....

#include <stdio.h>

int main() {

int i = 3;
if(!i) //this becomes false,
i++; //so it won't execute..
i++;. //this executes so I=4 now
if (i==3) //4==3 false
i += 2; //it won't execute
i += 2; //it executed so I=4+2=6
printf("%d",i); //here it prints 6
return 0;
}

//Is it clear?

edit:
!i=>!3 => false,
generally any number other than 0 is true, so negating it becomes false..

Answer 2

Jayakrishna🇮🇳 Thanks for the answer 🙂

It was a Quiz Challenge Question

Answer 3

Yes..
You're welcome...