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Items inside list
For ex. I have a list of ([[2,1], [2,3], [1,3]]) I want something like dominoes while ([[1,2], [2,3], [3,1]]) I use index.reverse but does't work... How to change the positions of numbers inside list or whatever...
4 Antworten
+ 5
Works fine!
a=[[2,1],[2,3], [1,3]]
a[0].reverse()
a[2].reverse()
print(a)
+ 1
Abhay thanks mate. I did't use "()" after reverse 💪💪☘
+ 1
Abhay
n = 0
for i in range(n,7):
print(
n, ":" ,i," "*5,
1, ":" ,i," "*5,
2, ":" ,i," "*5,
3, ":" ,i," "*5,
4, ":" ,i," "*5,
5, ":" ,i," "*5,
6, ":" ,i," "*5,
)
i +=1
Output it gives is not what I want.
0 : 0 1 : 0 2 : 0 3 : 0 4 : 0 5 : 0 6 : 0
0 : 1 1 : 1 2 : 1 3 : 1 4 : 1 5 : 1 6 : 1
0 : 2 1 : 2 2 : 2 3 : 2 4 : 2 5 : 2 6 : 2
0 : 3 1 : 3 2 : 3 3 : 3 4 : 3 5 : 3 6 : 3
0 : 4 1 : 4 2 : 4 3 : 4 4 : 4 5 : 4 6 : 4
0 : 5 1 : 5 2 : 5 3 : 5 4 : 5 5 : 5 6 : 5
0 : 6 1 : 6 2 : 6 3 : 6 4 : 6 5 : 6 6 : 6
I want all numbers to start with theirselves until 6(6 included)
I want 0:0 until 0:6
Then 1:1 until 1:6
2:2 --> 2:6
3:3 --> 3:6
4:4 --> 4:6
5:5 --> 5:6
and 6:6
Total of 28 couples... dominoes set
Where is my mistake??
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Arsen Lufo you should open a new question for this problem as it has nothing to do with original question . But i will try to look into it later on .