I need help

Question

Question👇
You are making a program for a bus service.
A bus can transport 50 passengers at once.
Given the number of passengers waiting in the bus station as input, you need to calculate and output how many empty seats the last bus will have.

Sample Input:
126

Sample Output:
24

Explanation: The first bus will transport 50 passengers, leaving 126-50=76 in the station. The next one will leave 26 in the station, thus, the last bus will take all of the 26 passengers, having 50-26=24 seats left empty.

This is my code 👇
#include <iostream>
using namespace std;

int main() {
//your code goes here
int num;
cout <<"enter the number of passengers:\t"<<endl;
cin>>num;
int busSeats=50;
int next_station=num%busSeats;
int seats_free=busSeats-next_station;
if(num>=50){
cout <<"seats is"<<seats_free;

}
else{
cout<<"seats is \t"<<50-num;
}

}

Answer 1

It's not necessary to add extra information in your solution
I mean your output should be matched with expected output

#include <iostream>
using namespace std;

int main() {
//your code goes here
int num;
//cout <<"enter the number of passengers:\t"<<endl;
cin>>num;
int busSeats=50;
int next_station=num%busSeats;
int seats_free=busSeats-next_station;
if(num>=50){
cout <<seats_free;

}
else{
cout<<50-num;
}

}

Answer 2

#include <iostream>
using namespace std;

int main() {
//your code goes here
int num;
//cout <<"enter the number of passengers:\t"<<endl;
cin>>num;
int busSeats=50;
int next_station=num%busSeats;
int seats_free=busSeats-next_station;
if(num>=50){
cout <<seats_free;

}
else{
cout<<50-num;
}

}

Answer 3

Yeah you nailed it. Thank you❤

Answer 4

What's the problem? Mentioned them

Answer 5

But they have shown that my code is not match with the expected output

Answer 6

F.MOHAMED THOUFIC YOUSUF

No need to write if else. Just use modulus operator like:

cout << 50 - num % 50;

Answer 7

Ok bro. No no ok pro