How do i prevent my Action class from executing my action_method when i create an Action object and then run Invoke_action()?

Question

https://code.sololearn.com/cbKQ2eqr5pqo/?ref=app

Answer 1

You probably want to pass a function to your Action object, without actually executing it, because you are storing the actions in a list. You can do this by passing a parameterized lambda as argument.

So in your World class when you instantiate the actions, you could do something like:

self.add_action(Action("You fell in a ravine and you are looking for a way out.", "You lost 50 health to fall damage", 40, lambda: self.player.take_fall_damage(50)))

and in the invoke_action method you would actually run the lambda by adding parentheses:

if self.action_method != 0:
print("i execute the action method")
return self.action_method()

Not sure if this will work flawlessly with the rest of the code, but this is the principle.

Answer 2

Tibor Santa ty for your solution, it works like a charm.

Answer 3

I tried adding a boolean but that does not work.

Answer 4

Here i define my action, i want the function to not execute from the constructor but if i call the invoke function i want to execute the method (see Action class at the bottom):

self.add_action(Action("You fell in a ravine and you are looking for a way out.", "You lost 50 health to fall damage", 40, self.player.take_fall_damage(50)))

class Action:
def __init__(self, action_sentence, action_response, action_probability, action_method = 0):
self.action_sentence = action_sentence
self.action_response = action_response
self.action_probability = action_probability
self.action_method = action_method

def invoke_action(self):
rand_percentage = random.randrange(100)
if rand_percentage <= self.action_probability:
print(self.action_sentence)
print(self.action_response)
if self.action_method != 0:
print("i execute the action method")
return self.action_metho