Why it keeps saying 'no output'

Question

https://code.sololearn.com/cfYlU6Pu3UDG/?ref=app

Answer 1

Because you declared the continue before n+=1 so when a odd number comes it becomes an infinite loop as the value of n never increases.So if you declare n+=1 before continue, it will work fine.
Btw, no need to write the else statement. You could just write the n+=1 after the if statement instead of declaring inside if and it would work the same as you expected:
https://code.sololearn.com/cqzrOK9RdDaB/#py
Also using for loop is a much better option as @Lothar mentioned.
You can make your code even shorter by using the built-in function sum and filter and using lambda.Like this:
https://code.sololearn.com/c2DTGo0q4kZD/#py

Answer 2

Mas'ud Saleh ,

# you don't need an else clause (it contains only a 'continue' that is useless in this case and the increment) and there is also no need to increment 'n' at multiple places:
[Edited]: # >>> please don't use names of python objects or classes like 'sum' as variable names !

items = [23, 555, 666, 123, 128, 4242, 990]

sum_ = 0
n = 0
while n < len(items):
num = items[n]
if num%2==0:
sum_ += num
n += 1
print(sum_)

# using a for loop is the better and more pythonic way of iterating: no need to calculare the length of the list, and no need to use a counter variable 'n':

items = [23, 555, 666, 123, 128, 4242, 990]

sum_ = 0
for num in items:
if num % 2 == 0:
sum_ += num
print(sum_)

Answer 3

You put n += 1 after continue so it never runs when you get to a odd number it while just run forever

Answer 4

continue before n += 1 may be causing an infinite loop…