[SOLVED] What's wrong with this code?

Question

//This code is not working. 😢
//Expected output: 15 1000 abc (in different line)
#include <stdio.h>
int main(){
int a=10,b=5;
float salary = 1000.00;
char name = 'abc';
int c=a+b;

printf ("%d \n", c);
printf ("%f \n", salary);
printf ("%c \n", name);
return 0;
}

Answer 1

Because you can only store one character in char value.
What you can do is to use an array.Like this:
char name[]="abc"//remember the quotation must be in double quote.
Then print the name as string.
printf("%s",name);
If you don't want the additional 00 in the end of the salary you can declare the salary to int or you can use printf("0.0f \n",salary);//but it will round the salary to the nearest int.
Here's the code:
https://code.sololearn.com/csA3AaojYYM2
Next time please try this:
https://www.sololearn.com/post/75089/?ref=app

Answer 2

Thank you very much 😇