Why does the output shows,whatever number I give as input shows as child..

Question

https://code.sololearn.com/cdnRue5Uwkt1/?ref=app

Answer 1

ABHINAV RAVIKRISH R Here are two codes that might help:

#1
age = int(input())
if 0 < age < 11: print("child")
elif 10 < age < 21: print("whatever")
elif 20 < age < 31: print("adult")
else: print("Not acceptable")

#2
if age > 30 or age < 1:
print("Not acceptable")
elif age > 20:
print("adult")
elif age > 10:
print("whatever")
else:
print("child")

# Hope this helps
# Happy coding!

Answer 2

Because your syntax is not proper. It should look like :
if 1 <= Age <= 10:

rather than what you have

Answer 3

Okay. This line:
if Age >= 1 <= 10 will always evaluate as True as long as Age is greater than or equal to 1.
Age >= 1 is True (i.e "1") and since 1 is always less than 10, the statement is True.

Answer 4

ABHINAV RAVIKRISH R The first statement will always execute given that the input is a natural number. I hope it helps. Happy coding!

Answer 5

Can you elobrate..I couldn't understand

Answer 6

Okk..I will try it..thanks

Answer 7

ABHINAV RAVIKRISH R I've posted a comment on your code. You may read that for a better understanding on this topic.

Answer 8

When I gives the input as 30 it shows child??can anyone give an example for it pls..I couldn't understand correctly

Answer 9

Or just:

if 0 < Age < 11: ...

as the input is an integer