Python

Question

What is wrong with this code??

import math
data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
#your code goes here
people = 0
for x in data:
for i in x:
people += i
if color == 'brown':
print(math.floor(((data[0][0]+data[1][0]) / people) * 100))
elif color == 'blue':
print(math.floor(((data[0][1]+data[1][1]) / people * 100))
elif color == 'green':
print(math.floor(((data[0][2]+data[1][2]) / people * 100))
elif color == 'black':
print(math.floor(((data[0][3]+data[1][3]) / people * 100))

Answer 1

Missing closing brackets in all elif conditions .

Answer 2

Yousif yes

Answer 3

Yousif what do you mean ? It works fine for me . I don't know about test cases or the question itself , so can't help with that unless you let us know about it!!

Answer 4

Yousif Here's how you can shorten your code:

data = ... # the data
people = sum(y for x in data for y in x)
k = ("brown", "blue", "green", "black").index(input())
print((100 * (data[0][k] + data[1][k]) / people) // 1)

# Assuming that I haven't made any error in my answer, I hope that this helps you with your query. Happy coding!

Answer 5

Abhay you mean parenthesis?

Answer 6

Abhay it did not work :(

Answer 7

Abhay You are right, it is not about cases though, it gives me an error message it tells me that my code has syntax error

Answer 8

data = [
[23, 11, 5, 14],
[8, 32, 20, 5]
]
color = input()
#your code goes here
brown = data [0][0] + data [1][0]
blue = data [0][1] + data [1][1]
green = data [0][2] + data [1][2]
black = data [0][3] + data [1][3]
sum = brown + blue + green + black
if color == 'brown' :
x = brown / sum
elif color == 'blue':
x = blue / sum
elif color == 'green':
x = green / sum
else:
x = black / sum

x *= 100
print (int (x))

Try this one it really works