Default Argument not updated? (Python)

Question

How can one modify this code so that the default argument changes based on value of variable i instead of copy?

a=1
def func(n=a):
print(n)
a+=1
func()

Answer 1

The best way to do that using function or object.
eg.

https://code.sololearn.com/cGiHZJK1G8cr/?ref=app

Answer 2

I think you'd have to use a class

class Foo:
a = 1
def __init__(self, n=a):
self.n = n

def func(self):
print(self.n)

my_var = Foo()
my_var.func()

# output
1

Answer 3

Delicate Cat
In the code, incrementing the variable a to 2 does not change the default argument in the function func to 2. I want to know if there is a clean way to have the default argument in func get updated along with the variable a

Answer 4

You set the new value for 'a' but it doesnt update the value of 'a' in the function unless you explicitly update it by passing an updated argument

a = 1
def func(n=a):
print(n)
a += 1
func(a)