Java 18.2 safety is first

Question

Password 8819.

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);

int password;
do {
System.out.println("Write password");
password = read.nextInt();
if (password == 8819){
break;
}else if ( password != 8819){
System.out.println("Write password");
}
} while ( password == 8819);

}
}

And I’m always getting the troubles with 4th test. Idk what the ??

Answer 1

Filin Oleg

do {
password = read.nextInt();
//Print
} while (password != 8819);

Just do like this.

You have unnecessary checking instead you can just check in while case. That's what the actual use of do while loop.

Answer 2

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);

int password;
do{
System.out.println("Write password");
password = read.nextInt();
//System.out.println(password);
if ( password == 8819){
break;
}else if (password != 8819){
// System.out.println("Write password");
}

}while (password != 8819);
}
}

Answer 3

At first i thought that while is going to loop while result is negative.

Answer 4

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int password;

do{
int x = 1;
password = read.nextInt();
System.out.println("Write password");
x++;

} while (password != 8819);
}
}

Answer 5

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int password;

do{
int x = 1;
password = read.nextInt();
System.out.println("Write password");
x++;

} while (password != 8819);
}
}