Why are 2 stack push statement needed here ??

Question

public class stack {
static void stack_push(Stack<Integer> stack){
        System.out.println("Push Operation:");
for(int i = 0; i < 5; i++)
{
stack.push(i);
            System.out.print(" "+i);
            }
        System.out.print(" \n");
}
// Popping element from the top of the stack
static void stack_pop(Stack<Integer> stack)
{
System.out.println("Pop Operation:");
for(int i = 0; i < 5; i++)
{
Integer y = (Integer) stack.pop();
System.out.print(" "+y);

}System.out.print(" \n");
    }
// Displaying element on the top of the stack
static void stack_peek(Stack<Integer> stack)
{
Integer element = (Integer) stack.peek();
System.out.println("Element on stack top: " + element);
}
static void stack_search(Stack<Integer> stack, int element)
{
Integer pos = (Integer) stack.search(element);}
public static void main (String[] args)
{
Stack<Integer> stack = new Stack<Integer>();

stack_push(stack);
stack_pop(stack);
stack_push(stack);
stack_peek(stack);
stack_search(sta

Answer 1

Once u popped the value from stack, the stack is empty. So again push value to the stack to perform other operations