I was successful in creating a code for the PIN card question, but I am still lost on the logic. Can someone help? (Try & Except

Question

We need to create a program that allows users to create their own PIN codes for their bank cards. Each PIN code consists of digits. Complete the program so that when the user enters a character, the program stops and outputs "Please enter a number" and when the user enters only digits, the program outputs "PIN code is created".

Sample Input
44a5

Sample Output
Please enter a number

CODE CREATED:

pin = input()
try:
#your code goes here
for i in pin:
if not i == int(i):
#print(not i == int(i))
# x= (int(i) + 0)
x = "PIN code is created"
print(x)

except :
#and here
print("Please enter a number")

Answer 1

Simon Varghese # is use for comments in python so all the lines that has # in their starting are not read by the python interpreter & treated as a comment.

Answer 2

1. You're asking user input in the pin variable.

2. Try & except block for catching any errors if your input ended up being a character then instead of showing the error program will simply execute the except block where you have a error free message that says please enter a number. ( by error free i mean it doesn't look ugly on the console aside from that it is still an error).

Answer 3

Thanks!!!

Answer 4

Thanks Zexu

But can you pls break down the code that I created inside the TRY block( Avoid the codes that has the # key attached to it)

Answer 5

Hi Simon!
Instead of using for loop to check each characters one by one, you can try this

pin = input()
try:
pin = int(pin)
print("PIN code is created")

except ValueError:
print("Please enter a number")

Answer 6

#Please find my code below and let me know your thoughts, Thanks :)

try:
pin = int(input())
print("PIN code is created")
except:
print("Please enter a number")