How do v_table and v_ptr work internally?

Question

Are v_tabkes of base class inherited by derived class?
Class Base
{
Public :
Virtual void print()
{
Cout <<"Base print "<<endl;
}
};

Class Derived : public Base
{
Public:
Void print()
{
Cout<<"Derived print"<<endl;
}
};

Int main()
{
Derived d;
Base* b= &d;
b->print();
Return 0;
}

Here is Derived having its own new set of v_table, or is it inheriting Base v_table and appending new virtual funcs in Derived, if any?
Will Derived get only the overriden virtual func of the Base or the Base v_table as such?

Answer 1

/*

V-tables (or virtual tables) are how most C++ implementations do polymorphism. For each concrete implementation of a class, there is a table of function pointers to all the virtual methods. A pointer to this table (called the virtual table) exists as a data member in all the objects. When one calls a virtual method, we lookup the object's v-table and call the appropriate derived class method.

For all it's worth, it is not a standard C++ terminology. It is just an implementation detail used by the implementation to implement virtual functions/dynamic binding

*/

Reference from stackoverflow

For more info https://practice.geeksforgeeks.org/problems/what-are-vtable-and-vptr

Answer 2

"Every class that uses virtual functions (or is derived from a class that uses virtual functions) is given its own virtual table." ..thank you sir...

Answer 3

Refer this post you will get better explanation
https://www.programiz.com/cpp-programming/virtual-functions

Answer 4

Cud u pls explain the internal working with v_ptr and v_table?