Count down project

Question

Count down project

You need to make a countdown app.
Given a number N as input, output numbers from N to 1 on separate lines.
Also, when the current countdown number is a multiple of 5, the app should output "Beep".

Sample Input:
12

Sample Output:
12
11
10
Beep
9
8
7
6
5
Beep
4
3
2
1

There's a code below this question please I need an explanation for it

Answer 1

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;

if (n<0){
cout << "Time cannot be negative"<< endl;
cin >> n;

}
// minimum countdown value is 1. hence, 0 is not an acceptable output so condition to use is n > 0 or you can use n>=1.
// for each countdown, you decrease the previous value by 1. written as n-- .

for (n ; n> 0 ; n--) {

// condition for beep (Number must be divisible by 5)
// challenge requires that you display the value which is divisible by 5 before displaying the Beep. So we display both outputs

if ( n%5 == 0 ){
cout << n << endl;
cout << "Beep" << endl;
}

else {
cout << n << endl;
}
}

return 0;
}

Answer 2

There are some comments in the code that explain it. Which part precisely do you struggle with?

Answer 3

For each count down u reduce the number by one? Why?

Answer 4

And what numbers are divisible by 5 in this code?

Answer 5

And what does multiple of 5 mean?

Answer 6

n-- because it counts downwards, for example: 9, 8, 7, ...

A number is divisible by 5 if (n % 5) == 0

% is the modulo operator, it gives us the remainder of a division. If the remainder equals 0 we know there is remainder, hence it is fully divisible by 5