0

Letter Counter(FAQ)

This is working code: text = input() dict = {} for i in text: if i in dict: dict[i] += 1 else: dict[i] = 1 print(dict) Please explain to me how text value come into dictionary? I can`t understand how it work.

4th Nov 2021, 8:48 PM
Вадим Томилов
5 Antworten
+ 2
Each letter from input text is extract by for loop and by if part, tested if it's in dictionary, if yes then its value at that letter as key is incremented. otherwise with that letter as key is added a value 1 by else part ex: input 'letter' i='l' , is in dict , false so dict['l']=1 i='e' , is in dict , false so dict['e']=1 i='t' , is in dict , false so dict['t']=1 i='t' , is in dict , true so dict['t'] +=1, dict['t']=2 i='e' , is in dict , true so dict['e'] +=1, dict['e']=2 i='r' , is in dict , false so dict['r']=1 Hope it helps...
4th Nov 2021, 9:10 PM
Jayakrishna 🇮🇳
+ 2
? Mark? Is it mean not clear yet? In for loop: That is, with each iteration of the "for" loop, By else part : each new letter from the input text is entered into the dictionary, or By if part : the value of the letter that is already in the dictionary increased by 1. Now hope it clear..
5th Nov 2021, 11:58 AM
Jayakrishna 🇮🇳
+ 1
With the for loop you've already got every single character(i) in the text. You need to write code like dict[i] = 1 to add it to this dictionary. This adds i as the key and 1 as the values ​​of i to the dictionary.
4th Nov 2021, 9:14 PM
Lütfi Burak ATMACA
Lütfi Burak ATMACA - avatar
+ 1
That is, with each iteration of the "for" loop, each new letter from the input text is entered into the dictionary, or is the value of the letter that is already in the dictionary increased by 1? Thanks for everybody!!!
4th Nov 2021, 11:01 PM
Вадим Томилов
+ 1
It was just thinking out loud with a question mark. I got it. Thanks again!
5th Nov 2021, 12:46 PM
Вадим Томилов