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Python for beginner 21.1

year = int(input()) #your code goes here b = year % 4 c = year % 100 d = year % 400 if c == d: print("Leap year") elif b == c: print("Not a leap year") elif b == 0: print("Leap year") elif c == 0: print("Not a leap year") elif d == 0: print("Leap year") else: print("Not a leap year") Every case is solved except case 5 i will post the rest you need in the comments. Just a hint no complet solution pls

4th Jan 2022, 9:38 PM
Sasha Krömtz
5 Antworten
+ 4
You need to remove the first if (c==d)statement and make d==0 as first condition
5th Jan 2022, 6:53 AM
Simba
Simba - avatar
+ 1
Simba , instead of providing ready code, pls prefer to point out errors and give conceptual hints on the way to solve. By solving the code themselves from our hints, the posters learn for real.
5th Jan 2022, 2:06 PM
Emerson Prado
Emerson Prado - avatar
0
You need to make a program to take a year as input and output "Leap year" if it’s a leap year, and "Not a leap year", if it’s not. To check whether a year is a leap year or not, you need to check the following: 1) If the year is evenly divisible by 4, go to step 2. Otherwise, the year is NOT a leap year. 2) If the year is evenly divisible by 100, go to step 3. Otherwise, the year is a leap year. 3) If the year is evenly divisible by 400, the year is a leap year. Otherwise, it is not a leap year. Sample Input 2000 Sample Output Leap year Use the modulo operator % to check if the year is evenly divisible by a number.
4th Jan 2022, 9:38 PM
Sasha Krömtz
0
Thats the lesson i have to solve
4th Jan 2022, 9:39 PM
Sasha Krömtz
0
Pls link your code from code playground using + button inside your question. This allows us to test, what always helps us to help you. That said, these comparisons doesn't make sense. For example: why year % 400 == year % 100 makes it a leap year? My hint: do the comparisons in the same order as the checks you listed in your answer.
5th Jan 2022, 3:00 AM
Emerson Prado
Emerson Prado - avatar