Fuzzy Search #need help

Question

#I need help!!!
# i want print second value and " Not found" if it not in dictionary

contacts = {
"David": ["123-321-88", "[e-mail]"],
"James": ["241-879-093", "[e-mail]"],
"Bob": ["987-004-322", "[e-mail]"],
"Amy": ["340-999-213", "[e-mail]"]
}
#your code goes here
a=input()
b=contacts.get(a,"Not found")
print(b)

Answer 1

b=contacts.get(a,[0,"Not found"])[1]

Answer 2

So [1] is the element of value of it
Thank you...

Answer 3

Looks good, what's wrong?

Answer 4

I mean second value, print out Second value of dictionary, you can see email right there

Answer 5

They want only email not include number phone

Answer 6

contacts.get(a,"Not found") return a list, so you see

Answer 7

Use judgment statements
or
replace the "Not found" with a list like [None, "Not found"]

Answer 8

Simba
Others always told me don't write the code of result directly instead of guiding him/her to think about the solution.

Answer 9

If a in contacts:
print (contacts[a][1])
else:
print ("Not found")