How is return used in java. This code tells me that the return I used is error .why?

Question

public class Program {

public static void main(String[] args) {
int x=50;
int y=70;
Math.max(x,y);
if(x<y){
System.out.println(x);
}
else{
return y;
}
}

}

Answer 1

Tony Jadesola

First thing main method has return type void means main method doesn't return anything.

2nd thing you have to assign Math.max(x, y) to a variable because max has return type which return something.

3rd thing if you want to get max value through comparison then you have to create a method which should have return type int and should return value in if and else both case.

So here is user defined method:

int getMaxValue(int x , int y) {
if (x > y) {
return x;
} else {
return y;
}
}

Now call this method and paas arguments x and y.

Remember you have to assign returned value to a new variable or you can directly print method.

using inbuilt method:

int result = Math.max(x, y);

Answer 2

main method in java is void return type. Don't expecting anything to return.
Then return y; invalid.
Where its return, to whom?

Tony Jadesola What are you trying by that line?