Go through the string below and if the length of a word is even print "even!" str = 'Print every word in this sentence that

Question

Expected Ouput:
[
'word = even!',
'in = even!',
...
]

My code:
def even(str):
str = str.split()
for a in str:
if len(a)%2 == 0:
a += 'even!'
print (a)

Answer 1

Jaz

I didn't understood your code, what you are doing there :|

So, here's the code:

txt = "Print every word in this sentence that"
x = txt.split()
print(x)
print()
for word in x:
if len(word)%2==0:
print([word,'even!'])
else:
print([word, 'odd!'])

Answer 2

Jaz
I would like to propose a different method using a def as per your original concept.

The def assesses the length of the word and prints the output if it is even.

I created an external loop and iterated the function through the items of the list

str = 'Print every word in this sentence that'

def even(txt):
if len(txt)%2 == 0:
print(txt," -> even")

for i in str.split(" "):
even(i)

Answer 3

Help

Answer 4

Hi АлКа Релова, we need to input a sentence (say: Hello world)

Now the program will calculate every word whether it's odd or even (not the whole sentence).
Like:

Hello: odd
World: odd

edit]: you can share your program too🙄

Answer 5

Your code??

where you are getting problem??

Answer 6

NEZ it separately prints the words like this:

['words = even!']
['In = even!']

Answer 7

Jaz

So where is your code??

Have you tried anything towards this problem??

we won't give direct answers here 🙄

Answer 8

Jaz

['Print', 'every', 'word', 'in', 'this', 'sentence', 'that']

['Print', 'odd!']
['every', 'odd!']
['word', 'even!']
['in', 'even!']
['this', 'even!']
['sentence', 'even!']
['that', 'even!']

[Program finished]

//

Is this output you want to print??

Answer 9

NEZ Yep

Answer 10

NEZ thanks for the big help

Answer 11

АлКа Релова i did a different code.

Answer 12

Hi