What is wrong with this code please:n = 100 i = 1 while i <= n: if i % 2 == 0: continue print(i) i+=1

Question

I want to print numbers from 1 to 100 excluding those divisible by 2

Answer 1

continue cause to skip next statement so it can't reach i+=1 when I=2 and stays there forever , making infinite loop...

Add code in description place...

edit:
NonStop CODING
if that is your complete code, then it stil infinite loops.. check again..

correct better way is what Lean R1 found.👍

Answer 2

Thank you very much guys for the help.
I have rewritten the code still using *continue* like this:

n = 99
i = 0
while i <= n:
i+=1
if i % 2 == 0:
continue

print(i)

And it's running well

Answer 3

write i+=1 inside if block to increment i when I is divisible by 2. do this to avoid infinite loop

or you can do this by without using continue

Just write

n = 100
i = 1
while i <= n:
if i % 2 != 0:
print(i)
i+=1; # i++

Print for those who are not divisible by 2

Answer 4

Lean R1 it is more appropriate to use a for loop than using while to loop for a fixed number of iterations. Also, if the index skips consistently at a regular interval (e.g., 2 for odd numbers), then code the interval into the range and eliminate the if statement:

n = 100
for i in range(1, n+1, 2):
print(i)

Answer 5

wowwww! thanks guys🙏🙏🙏

Answer 6

Jayakrishna🇮🇳

Fixed😎

thanks for mentioning👍

There was a Indentation mistake😁😁

indentation are really important!

Answer 7

n = 100
i = 1
while i <= n:
print(i)
i+=2

🙄,You can do that thing without using if/else too...

Answer 8

print(*[i for i in range(1,100,2)], sep="\n")

Or this😄😉

Answer 9

print(*range(1,100,2), sep="\n")

#or this 😄😉from @Nez's

Answer 10

NEZ
Jayakrishna🇮🇳

Impressive!😍

Nailed it bros! 🔥🔥

Answer 11

Lean R1

Yeah you can do this way as well👍

Answer 12

NonStop CODING thank you 🙏🙏🙏

Answer 13

NonStop CODING
Yes. now..👍
But it about using continue from lesson.. 😇
still fine. no problem.. You're welcome...

Answer 14

ANONYMOUS

😁😁😁

Excellent Observation!✌️

you insipired me to short down this code further,

instead of running the full loop, we can reduce the loop iteration to half, by doing this we can save 50% time 🤓🤓

n=100;
i=0;

while i < int(n / 2):
print( 2 * i + 1 )
i += 1

Answer 15

Brian
yeah Great!🤓🤓