Why does this code act this way??

Question

An input of any number higher than 2 shouldn’t print “success”. Can anyone help please!!!

https://code.sololearn.com/chXur71ZovM3/?ref=app

Answer 1

Correct syntax:
while True:
num = int(input()
if num == 1 or num == 2:
Or

while True:
if int(input()) in [1,2]

Answer 2

Because of the operators precedence.
Since `==` operator has higher precedence than or operator, it's treated as
(int(input()) == 1) or 2.
If input is 1, True or 2 else False or 2.
So, if statement is always executed since it returns True for any input.

Answer 3

Sammy Jamez

You can understand better through this example:

a = False
b = True
c = True

print (a and b or b and c)

This works like:

print((a and b) or (b and c))
print(False or True)
print(True)

--------

a = True
b = False
c = True

print (a and b or c)

This works like:

(a and b) or c

------------

a = False
b = False
c = True

print (a or b and c)

this works like:

a or (b and c)

-----------------

a = False
b = True
c = True

print (a and b or c)

this works like:

(a and b) or c

Answer 4

Sammy Jamez
Either way, even if you can structure the code correctly, putting the input in a while loop will not work in Sololearn.
It will work in Pydroid or a proper computer ide with a terminal output, but not with Sololearn's input system.
The code below works in Pydroid, but not here in Sololearn. You just can't put the input in a while loop in Sololearn's playground.

print("May we start?\n\t1. Yes\n\t2. No")

while True:
if input() in ("1", "2"):
print("success")
break
else:
print("You have to pick betweeen 1 or 2")
print("May we start?\n\t1. Yes\n\t2. No")
continue

Answer 5

num = int(input())
While True:
If num == 1 or num == 2:
print("success")

That's the syntax for the line that triggers the error

Answer 6

Sammy Jamez

int(input()) == 1 or 2

This works separately means before the 'or' is one condition and after the 'or' is another condition

So int(input()) == 1 might be false on any number except 1 but after the 'or'

2 will always return true

Answer 7

Sammy Jamez

Any number except 0 will always give True

Answer 8

Thank you!!

Answer 9

You forgot to add the break at the end of the if statement

Answer 10

Have started

Answer 11

Wow but why doesn’t the one in the code do the right thing??

Im so confused right now…

Answer 12

int(input()) == 1 or 2
is true if either
int(input()) == 1
or
2
is true.
In Python any integer other than 0 is evaluated as True.
So your condition is always true.

Answer 13

Wow i get the before the or but after the or, should it return true for other numbers asides 2

Answer 14

Wow thanks a lot guys✊🏽

It was helpful…

Answer 15

Before coming to sololearn, i tried with pycharm… it was there the question came from. So its not bout Sololearn, its the code itself

Answer 16

Sammy Jamez
You are right, there is an issue in your if condition. I modified your code so it works, but it really would never work in Sololearn.

Answer 17

Wow you mind sharing the modified code?

I’d just rewrite it on PyCharm and run it there…

Answer 18

Sammy Jamez
just change the if statement

if input() in ("1", "2"):

also maybe add a break inside the if block?
look at my answer above

Answer 19

Sammy Jamez
Try it in Sololearn to see how much the input system cripples the Python learning experience.

Answer 20

Shreyaansh

Why though🤔