Smallest number to the right of the number in a list

Question

If i have a list- [9, 0, 7], how would i check if 7 has a smaller number to the right of it, in which case it doesnt, and for 9 it would be 0

Answer 1

Is there possibility of duplicate values in the list? if not, you can try slicing from the index of 7 and use any( ) to check whether there is any number smaller than 7.

It might worth considering to assume no such number when number of 7 was the last item.

Answer 2

Ipang what if there are duplicates?

Answer 3

Guess we have to make sure which 7 it was to check ...

(Edit)
This was what I had in mind, no duplicate value was expected though ...

lst = [ 9, 0, 7 ]
fun = lambda iter, n : any( val < n for val in iter[ iter.index( n ) : ] )
print( fun( lst, 9 ) )
print( fun( lst, 7 ) )

Answer 4

You can check in this way also
p=[9,0,7]
m=p.index(7)
for i in range(0,m):
if(p[i]<p[m]):
a=p[i]
print(a)
Hope you understood this :)