different solutions for the "zip code validator" challenge

Question

Hi everybody,

I solved the "zip code validator" in code coach with this code:

code = input()

if (len(code) == 5) and (code.count(" ") == 0) and (int(code)/1 == int(code)):
print("true")
else:
print("false")

---

I think there are more nice solutions possible - what are your ideas?

Here is the task:

As headmaster of the post office, sometimes people write zip codes that don't exist or zip codes that are not valid.
You are tasked with making a system to check if the inputted zip code is a valid zip code.

Task:
Write a program that takes in a string representing a zip code. Output true or false if it is a valid zip code or not.
A valid zip code is only numbers, must be 5 characters in length, and contain no spaces.

Input Format:
A string containing a zip code.

Output Format:
A string: true is the input is a valid zip code, or false, if it is not.

Sample Input:
752f78

Sample Output:
false

Answer 1

You may try something like this

if code.isdigit() and len(code)==5:
print("true")
else:
print("false")

Answer 2

import re
pattern=r'\d{5}#x27;
if re.match(pattern,input()):
print('true')
else:
print('false')

# Course: Python Core
# Regular Expressions

Answer 3

import re

print(* ['true' if re.findall(r'^\d{5}#x27;, input()) else 'false'])

Answer 4

hey sir, your solve has a bug
please pay attention to it.
yours sincerely.

Answer 5

code=input()
if code.isdigit() and len(code)==5:
print("true")
else:
print("false")
Try some unique code
Definitely it will work

Answer 6

is your len(code)==5 working? because mine is not

Answer 7

zip_code = input()
if len(zip_code) == 5 and (zip_code.count(" ") == 0) and (int(zip_code)/1 == int(zip_code)):
print("true")
else:
print("false")
This solution passed every test cases.

Answer 8

try:
code = int(input())
if len(str(code)) == 5:
print("true")
else:
print("false")
except ValueError:
print("false")

This is my solution