Can you explain the output of this particular code ?

Question

Explain the output
https://code.sololearn.com/co1d1xru90P8/?ref=app

Answer 1

int a =1;
int b =1;
int c = a || --b;
The C language does short-circuit logic evaluation. Since a is non-zero, it skips evaluating --b. The expression evaluates to true, which gets stored as 1 in c. It leaves b as 1.

int d = a-- && --b;
Since a is 1, the left operand is seen as true. Then a gets decremented to 0. Now it must evaluate the right operand. First, b gets decremented from 1 to 0. Since the right operand is 0 (false) the whole expression evaluates to false, and 0 gets stored in d.
Now a=0, b=0, c=1, d=0.