How to output age as a string while taking in numbers

Question

I have tried this many a time, and it is for the golang second code. I want to take in numbers, and out put them as letters. This is an example of my code.

package main
import "fmt"

func main() {
//your code goes here
var a, b, c int;

fmt.Scanln(&a, &b, &c );

switch{
case a==0:
fmt.Println("Zero")
case a==1:
fmt.Println("One")
case a==2:
fmt.Println("Two")
case a==3:
fmt.Println("Three")
case a==4:
fmt.Println("Four")
case a==5:
fmt.Println("Five")
case a==6:
fmt.Println("Six")
case a==7:
fmt.Println("Seven")
case a==8:
fmt.Println("Eight")
case a==9:
fmt.Println("Nine")
case a==10:
fmt.Println("Ten")
default:
fmt.Println(a)
}
switch{
case b==0:
fmt.Println("Zero")
case b==1:
fmt.Println("One")
case b==2:
fmt.Println("Two")
case b==3:
fmt.Println("Three")
case b==4:
fmt.Println("Four")
case b==5:
fmt.Println("Five")
case b==6:
fmt.Println("Six")
case b==7:
fmt.Println("Seven")
case b==8:
fmt.Println("Eight")
case b==9:
fmt.Println("Nine")
case b==10:
fmt.Println("Ten")
default:
fmt.Println(b)
}
switch{
case c==0:
fmt.Println("Zero")
case c==1:
fmt.Println("One")
case c==2:
fmt.Println("Two")
case c==3:
fmt.Println("Three")
case c==4:
fmt.Println("Four")
case c==5:
fmt.Println("Five")
case c==6:
fmt.Println("Six")
case c==7:
fmt.Println("Seven")
case c==8:
fmt.Println("Eight")
case c==9:
fmt.Println("Nine")
case c==10:
fmt.Println("Ten")
default:
fmt.Println(c)
}
}

Please, help me

Answer 1

I think your input is where the error is.

Your program takes input like this:

1 2 3

But the input is given like:

1
2
3

Because the way you get the input is wrong. The second and third number print "zero".

Answer 2

Thank you. so, do I just bring down the scan to separate values