Pls 🙏 how does this code works

Question

#include <iostream>
using namespace std;

int main() {
for (int i =0;i<40;i++){
if (i&5){cout<<i<<" ";}
}
return 0;
}

Answer 1

When i=0 if condition output is zero so condition is false so no output when i=0.
When i= 1 if condition statement output is 1 which is true so output is 1

Answer 2

code print only when if statement have greater than condition
when i= 0 (0000)&(0101) which will result as (0000)=0
when i=1 (0001)&(0101) which will result as (0001)=1
when i=2 (0010)&(0101) which will result as (0000)= 0
when i=3 (0011)&(0101) which will result as (0001)=1
when i=4 (0100)&(0101) which will result as (0100)=4

& (bitwise and operator work on bits
1&0 = 0
1&1 = 1
0&1 = 0
0&0 = 0
)

Answer 3

So what will be the output of the code?

Answer 4

the value of i for which the if condition true is output

Answer 5

Ayomo Joshua Odunayo to see the output you may run it yourself in the Code Playground.

It prints only numbers that have bit0 or bit2 set to 1. The value 5 (101 in binary) is used as a bit mask that allows bit0 and bit2 but blocks all other bits. If either bit is 1, then the conditional is true (non-zero); otherwise it is false (0).

Stated another way, the output would show odd numbers (bit0), and odd multiples of four (bit2) and their next higher even number.