+ 2
You are provided with two numbers. Find and print the smaller number.
You are provided with two numbers as input
28 Antworten
+ 10
a = int(input())
b = int(input())
if a < b:
print(a)
elif a > b:
print(b)
+ 9
a = int(input())
b = int(input())
print(min(a,b))
+ 5
* get 2 input()
* convert input to numeric data type
* use an if-statement and >= to compare the numbers
If you need help, please explain what your issue us.
+ 3
Please be exact about the expected input. If you get the input as 1 line, split the line at the separator. Then convert each element to a numeric data type. Then compare the numbers.
+ 2
input().split(",")
You get a list of strings: make each element an integer, then you can use min().
And PLEASE:
⭐⭐⭐Try to put your comments or additions in 1 comment instead of spreading each bit of information into an extra comment.⭐⭐⭐
+ 1
lis =[ ]
count = int(input())
for n in range(count):
number = int(input())
lis.append(number)
print(min(lis))
+ 1
Find smallest in the two numbers
25'2
+ 1
25,2
+ 1
You need only 2 inputs. Your code would require min 3 inputs to get the 2 numbers.
If you are referring to a sololearn task, mention course name and task number.
+ 1
We should write program without using hardcode
+ 1
That means input( )
+ 1
Int(input( )). split ("")...?
+ 1
l=[int(input() for _ in range(2)]
print(l[l[1]<l[0]])
+ 1
a, b = int(input())
if a > b:
print (a)
else:
print(b)
+ 1
print(min(int(input()), int(input())))
0
Question
0
a = int(input())
small = min(a)
print (a)
0
If I give input value
25,5
0
I am getting error:-
Invalid literal for int( ) with base 10
0
Because you need to split the input string at ",", THEN convert each element to int()