Why output ends with 'None'?

Question

def concatenate(*args):
for i in args:
i += "-"
print(i, end="")

print(concatenate("I", "love", "Python", "!"))

Answer 1

Because you are actually printing a seal 😉:
print(print())

You just need:
concatenate("I", "love", "Python", "!")

Answer 2

Your function does not return anything, that's why it prints None.

Either replace the print() in the function with return or remove the last print.

Answer 3

either construct a new string to return or remove the last print...

Answer 4

It is that if I change the print for the return it does not return the complete concatenation :(

Answer 5

It is possible to write this function without using a loop ☺️

Answer 6

'''
Oro Collares
you can use the sep parameter of print.
'''
#use directly
print('I', 'love','python', sep='-')

#use inside a function
def hypenate(*args):
print(*args, sep='-')

hypenate('print','is','a','function')

#if you want a string return value
def add_hypen(*args):
return '-'.join(args)

print(add_hypen('This','also','works'))

Answer 7

Bob_Li Thanks!!, i learn quite a lot with community interaction 🥰

Answer 8

Solo ahhhhhh, thanks so much😂😂🥰

Answer 9

You just need to add a condition to look for the last argument.

Answer 10

By the way, 'end' can be assigned any character you need.

Answer 11

My God it was making my life complicated, I just had to put "-".join(args) in the function, I'm going to finish more courses I loved them Solo 🥰🥰🥰

Answer 12

Yes, this is probably the easiest way, but what you tried to do without using "join" is good practice for logical thinking. 😎

Answer 13

if now I'm struggling to remove the last "-" so that it becomes valid, I don't know if that's a bad practice😅