shouldnt it be 7 because it says num==7 and num=7

Question

What is the output of this code?
num = 7
if num > 3:
print("3")
if num < 5:
print("5")
if num ==7:
print("7")

Answer 1

These are nested if blocks.
So,
if(num > 3) True
Goes inside prints 3
if(num < 5) False
Doesn't go inside. Hence none of the further code executed.

Answer 2

output is 3.
because 1st condition is true only so "if" condition evaluate true and print it

Answer 3

It will only print out 3.

The reason being when the code evaluates the line: if num < 5, it has evaluated false and everything inside the body will not be executed.

So, the output will only be 3.

Answer 4

Hello! here is my explanation:
num = 7 <---This is the given value
*if num > 3: <----This is the 1st condition, if it´s not satisfied then the program goes to condition #2
print("3")
*if num < 5: <---- This is the second condition,if not satisfied goes to condition #3
print("5")
*if num ==7: <----This is the third and final condition.
print("7")
As we can note, the number given is 7 and 7==7 right? Mathematically it is true, but the "If" condition in the program evaluates the input in a logical way as I explained above: Value given, if condition #1 is true the program ends, if not then evaluates condition #2, and so on. Because the first condition is TRUE (7 is greater than 3) then the program ends and the result is 3 because that is the instruction( print("3")).
*P.D. In fact we will never get to the final condition (7==7) because the program would end immediately in the first condition.
*P.D. Sorry if I do not explain myself clearly.

Answer 5

What i understand is that it finds a false statement and stops the execution.
I tryed to put the 7 statement before the 5, and it reads it