- 1
What is the problem here?
int x=9; while (x<19) { x= (x%3!=0) ? Console.Write(x) : Console.Write("*"); x++; }
7 Antworten
+ 1
In Javascript, x is undefined after the first ternary evaluation, and NaN after x++.
NaN compared with a number is false, hence the loop breaks.
+ 1
I was trying to explain it in my initial comment.
x = (x%3 != 0) ? A: B;
x will be reassigned by the end of the statement, it will either be A or B depending on the result of the evaluation.
If A is console.log(), x becomes undefined as console.log() doesn't return what it prints (undefined in Javascript)
In C# it will raise an error as Console.Write doesn't return either and "void" cannot be assigned to an integer variable.
+ 1
I think, it's just not the intended usage of the ternary operator.
You could just use a regular if-else statement or functions with return values.
https://code.sololearn.com/c2ttAt6aEHR0/?ref=app
0
In ternary operations, the result.of the comparison is assigned to the the variable (here x). However, ConsoleWrite() does not return an integer (it doesn't return at all). That's why an error occurs.
0
If your code is JavaScript, then:
var x=9;
while (x<19) {
x=(x%3!=0) ? console.log(x) : console.log("*");
x++;
}
0
yep, that's the problem. now it is clear why the cycle does not work. but why is x undefined? it is also set to 9 before the cycle.
0
excellent knowledge of the subtleties of language! what in this case needs to be done to avoid this phenomenon and the cycle has worked?