[Solved] Can you explain why the argument's appended as a whole tuple?

Question

def f(*y):
x.append(y)
return x

x = [3, 7]
f(2, 3, 4)
print(x)

out: [3, 7, (2, 3, 4)]

and not [3, 7, 2, 3, 4]

Thanks.

[edit; question before was: Can you explain why the tuple is appended as a whole after getting unpacked in the args? (py)

I had to change the wording for more accurate search results.]

Answer 1

Because the arguments when given in the *args format is a tuple. And when you append a tuple, it doesn't append the values seperately.

https://code.sololearn.com/cimc94VivtPT/?ref=app

Answer 2

That's due to the *y argument in the function which converts the values you've written in f() as a tuple
To correct this and print the values separately you can simply use the for loop inside the function and indent the append function inside the loop, such as this :
def f(*y)
for value in y:
x.apend(value)
return x
And your function is done 😁

Answer 3

Zen Ai Thank you.
I severely mixed up stuff here. Naming the f arg in my mind already as a tuple: wrong
Then treating that as a generator, then passing each of its elements one by one, wrong again. Lol.

I have to delete the "unpack" tag, it is misleading for people at my level or more novice.

Answer 4

Korkunç el Gato continues trials and errors and corrections of those errors leads to mastery✨✊

Answer 5

Slick Thanks a lot. Cure to my confusion.

Answer 6

*y still saves the arguments in tuple format