Explain the output.

Question

https://code.sololearn.com/cwCCon6st9hS/?ref=app

Answer 1

you have decleared variable x =5 in cout statement you incrementing value you have yse ++ two times and remember that alway expression solve from left to right . amd in alway first pre incremt or pre decrement will solve and assign then post . so first x++ will print 5 then value increase by 1 then second x++ here thus incremented value will print means 6 but here you have written x++ again and it will print 6 then value increased by 1 means 7 which is not using anywhere in program thats why it showing warning becz you not using 7 anywhere so try to avoid such types of calculation to your program becz it generate warnings and also its depend on compiler how it solve

Answer 2

Kumar Anshuman

int x = 5;

int y = x++; //first assign then increment by 1

cout << y; //5
cout << x; //6

Answer 3

I also wrote this code on GeeksforGeeks compiler and there it shows 65 as the output without any warning.

But here it shows 56 with a warning.

Why?
Please explain.

Answer 4

Please explain this

https://ide.geeksforgeeks.org/6e61fac7-2a68-4ada-a6a7-a75a1a1854ec