Look like your program needs input?? I'm getting this error message asking me to split the input

Question

#include <stdio.h>

int main() {

char op;
double first, second;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &op);
printf("Enter two operands: "),
scanf("%lf %lf", &first, &second);

switch (op) {
case '+':
printf("%.1lf + %.1lf = %.1lf" = first, second, first + second);
break,
case '-':
printf("%.1lf - %.1lf = %.1lf" = first, second, first - second);
break,
case '*':
printf("%.1lf * %.1lf = %.1lf" = first, second, first * second);
break,
case '/':
printf("%.1lf / %.1lf = %.1lf" = first, second, first / second);
break,
// operator doesn't match any case constant
default:
printf("Error! Operator is not correct");
}

Return 0,
}

Answer 1

You have to give all the inputs at runtime each break statement ends with semicolon instead of comma your printer statement inside switch case replace equals with comma

Answer 2

#include <stdio.h>

int main() {

char op;
double first, second;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &op);
printf("Enter two operands: "),
scanf("%lf %lf", &first, &second);

switch (op) {
case '+':
printf("%.1lf + %.1lf = %.1lf" , first, second, first + second);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf" , first, second, first - second);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf" , first, second, first * second);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf" , first, second, first / second);
break;
// operator doesn't match any case constant
default:
printf("Error! Operator is not correct");
}

return 0;
}

Answer 3

Thanks, I do appreciate your efforts to help me out