How to simplify this Tic Tac Toe program ?

Question

number = 3
matrix = []
for i in range(number):
string = input().split()
matrix.append(string)

if (matrix[0][0] == "O" and matrix[0][1] == "O" and matrix[0][2] == "O") or (matrix[1][0] == "O" and matrix[1][1] == "O" and matrix[1][2] == "O") or (matrix[2][0] == "O" and matrix[2][1] == "O" and matrix[2][2]) == "O":
print("Abhinav Wins")
elif (matrix[0][0] == "X" and matrix[0][1] == "X" and matrix[0][2] == "X") or (matrix[1][0] == "X" and matrix[1][1] == "X" and matrix[1][2] == "X") or (matrix[2][0] == "X" and matrix[2][1] == "X" and matrix[2][2]) == "X":
print("Anjali Wins")
elif (matrix[0][0] == "O" and matrix[1][0] == "O" and matrix[2][0] == "O") or (matrix[0][1] == "O" and matrix[1][1] == "O" and matrix[2][1] == "O") or (matrix[0][2] == "O" and matrix[1][2] == "O" and matrix[2][2] == "O"):
print("Abhinav Wins")
elif (matrix[0][0] == "X" and matrix[1][0] == "X" and matrix[2][0] == "X") or (matrix[0][1] == "X" and matrix[1][1] == "X" and matrix[2][1] == "X") or (matrix[0][2] == "X" and matrix[1][2] == "X" and matrix[2][2] == "X"):
print("Anjali Wins")
elif (matrix[0][0] == "O" and matrix[1][1] == "O" and matrix[2][2] == "O") or (matrix[0][2] == "O" and matrix[1][1] and matrix[2][0]) == "O":
print("Abhinav Wins")
elif (matrix[0][0] == "X" and matrix[1][1] == "X" and matrix[2][2] == "X") or (matrix[0][2] == "X" and matrix[1][1] and matrix[2][0]) == "X":
print("Anjali Wins")
else:
print("Tie")

Answer 1

Yeah there are a lot you can consider to make this more efficient.

first, you should have a function to check if the game is finished and has a winning move.

a winning game is three repeated character in a row, column or diagonal. so you can loop over each of those and validate if they are all identical

I can't add much more right now but I hope this helps!

Answer 2

No code is linked here

Answer 3

sry..

now pasted code