Can someone tell me what I'm doing wrong? Everything seems to be ok to me? 🥺

Question

/*If you were to visit houses, several give you candy, two houses give you dollars, and one house gives you a toothbrush. At the end of the tour. What is the probability (in %)of taking 1 dollar bill out of my bag?
Example
If you visited four houses, one would be candy, two would be dollars, and one would be a toothbrush. A 2 in 4 chan*/import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int houses = input.nextInt();

if(houses>=3){
double parte=houses-2;
double total=houses;
double uno=1;
double division=(uno-parte/total)*100;
int redondeo=(int)(division*10);

if(redondeo%10>=5){
int num=(int)division;
System.out.println(num+1);
}
else{
int num=(int)division;
System.out.println(num);
}
}
}
}

Answer 1

Hi Genniell just few tips to get better help,
its better to post a url to your code instead of posting it here in clear, the name of variables must be meaningful, also add some comments to your code, I think that's it 😁
about the problem: there is one house gives candy + 2 dollar bills and the fourth gives toothbrush, if there is fifth house, will gives candy,.. and so one

for simplicity : (. means no dollar)
(* means dollar bill)

h1 h2 h3 h4 h5
. * * . .

so if there is 5 houses , the percentage will be ~ 5/2 wich will be 100/(5/2) wich is 200/5;
so in general if you visited N houses the percentge will be 200/N;
so this you should round it up to the nearest integer.

Answer 2

Thank you very much I will take your advice into account