hiw to detect most frequency number in python array

Question

ex-
[1,1,2,6,6,6,6,9]
most frequency number is 6

[1,1,1,8,6,7,7,7,9]
most frequency number is 1 and 7

Answer 1

Damsara Welivita , Ｒｏｓｈａａｎ , Basil ,

> the use of statistics.mode(...) does not give a correct result if 2 numbers have the same number of occurrence. it only returns the first one.

> we can use statistics.multimode(...) instead.

see sample code in the file:

https://code.sololearn.com/cuqRZgC5EpeB/?ref=app

Answer 2

To find the most frequently occurring number in a Python list, you can use the Counter class from the collections module.

Answer 3

from collections import Counter

# Example arrays
arr1 = [1, 1, 2, 6, 6, 6, 6, 9]
arr2 = [1, 1, 1, 8, 6, 7, 7, 7, 9]

# Count the frequency of each number in the array
count1 = Counter(arr1)
count2 = Counter(arr2)

# Find the most common number(s) and their frequency
most_common1, freq1 = count1.most_common(1)[0]
most_common2 = count2.most_common(2)
freq2 = most_common2[0][1]

# Print the results
print(f"Array 1: {arr1}")
print(f"Most common number(s): {[num for num, count in most_common1]}")
print(f"Frequency: {freq1}")

print(f"\nArray 2: {arr2}")
print(f"Most common number(s): {[num for num, count in most_common2]}")
print(f"Frequency: {freq2}")

Answer 4

Use a dict, it is very easy and simple:

array = [1,1,1,2,4,6,6,7,7,7,7,7]

s_2 = {}
for i in array:
s_2[i] = s_2.get(i, 0) + 1

print(max(s_2.keys(), key = lambda k: s_2[k]))

In the code below: there is an additional code for numbers from the highest number of repetitions to the lowest number of repetitions

https://code.sololearn.com/cY9Q7sEB4v49/?ref=app