how do I sum elements 2 by 2 list? (python)

Question

so for example, i have a list:
l = [1, 2, 3, 4, 5, 6, 7, 8]
and so i want to sum all the numbers 2 by 2:
1 + 3 + 5 + 7 = 16

Answer 1

Create a "for" loop in increments of 2.
Or write a condition that checks odd numbers using the modulo division operator - "%".

Answer 2

If I understand correctly, you need to do the following:

1. Create a new list. Use list comprehension to retrieve numbers, from the original list, that you need in your new list.

2. Use sum() built-in function, or **for** loop to get total.

Answer 3

filter list by checking even index position of each values

Then use sum function to get total

print (sum([i for i in l if l.index(i) % 2 == 0]))

Answer 4

Python program to find sum of elements in list

total = 0

# creating a list

list1 = [11, 5, 17, 18, 23]

# Iterate each element in list

# and add them in variable total

for ele in range(0, len(list1)):

    total = total + list1[ele]

# printing total value

print("Sum of all elements in given list: ", total)

Answer 5

If I am wrong please correct me

Answer 6

Ok I understand