in a method PrintName , if i want to print name if i use " cout<<name;" it works , but not if i use " return name". Why?

Question

https://code.sololearn.com/cjj8nNJa5ZOb/?ref=appif

Answer 1

If you want to use return name, you have to change the return type of the method printNane , from void to string. The cout only prints on screen, the return returns something which is different.
https://code.sololearn.com/cUxl7vG6Hfo0/?ref=app

Answer 2

thank you! i was confused whith that