What is wrong in this No Numerals code coach solution

Question

So i have tried to make a No Numerals code with string format function like this :
str = input()
list = str.split()
output = ""
for x in list :
if x.isnumeric():
x = "{int(x)}".format("zero","one","two","three","four","five","six","seven","eight","nine")
output += x
else :
output += x
print(output)

But it says that there's a key error in int(x)

https://code.sololearn.com/cREgPfZdqzt9/?ref=app

Answer 1

I don't think you can use a variable as a numbered index for .format. idk why exactly though, or if that's broadly true or just a playground quirk ...just that it seems to be failing.

Also, assignment says to include 10, and you haven't handled punctuation (eg the previous 10 in this sentence), and you gotta add spaces back in between the words.

Answer 2

This Should be the correct code:

https://code.sololearn.com/c1XpHhYBFdCJ/?ref
=app

Answer 3

Arin The format() method was used incorrectly. Instead of providing the arguments as separate strings, you should pass them as positional arguments within the format string. Additionally, the int(x) part was placed within quotes, which made it treated as a literal string instead of evaluating the x variable as an integer.

Answer 4

Arin In the given code, "{:s}".format() is a string formatting technique used to convert a value into a string.

The "{:s}" inside the format function is called a format specifier. The :s specifies that the value should be formatted as a string.

Answer 5

Arin If you want to know how that works in that code, ask me I'll explain!

Answer 6

Arin , Orin Cook , Vibhor For some reason you all are stuck with the format() function, whereas it is not needed at all. You just take the dictionary as in the @Vibhior's answer, and take x-th element of that.
```
nums = dict(enumerate(("zero", "one", "two",... )))
output += nums[int(x)]
```

Answer 7

Arin the ":s" format specifier is not needed, because it is the default. https://docs.python.org/3/library/string.html#format-specification-mini-language

Answer 8

It says its fine

Answer 9

Orin Cook I see
Thanks
I'll find some other way to do this then

Answer 10

Alright, found a workaround:
thing = "{"+x+"}"
x = thing.format("zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine")

(Don't actually use "thing," it's a terrible variable name)

Also, forgot to mention a more critical problem here: test that x isn't a larger number before doing that, or else you'll get index out of bounds errors

Answer 11

(Oh, and a minor refinement: remove your else clause and just move output+=x outside of the if)

Answer 12

Orin Cook thanks
But can you please tell me what does the "+x+" do
Actually I'm a beginner so i don't know much about that

Answer 13

Oh lol, that just concatenates it, ie sticks the strings together. Kinda exactly what you'd naively expect adding strings would do.
note that it's
"{"
+ x
+ "}"

Answer 14

Vibhor I see
But can you please explain what does the :s do in x = "{:s}".format...

Answer 15

Sure, but we're trying to help fix code, not (re)write it from scratch. Plus, I'm learning more this way lol.