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How to solve "New driver's license" problem without using math.ceil, rather using this method below?
I try another method, 1. First I take input() from user and 2. define function that add user_name in other_4 list, 3. and .sort(), 4. then cut list in chunks by given "agendt_num" 5. Then order existing chunk number that where "me" object exist. 6. Lastly, print(existing_chunk_number * 20)
10 Antworten
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Vibhor ,
> it is not seen as a helpful behavior when we are going to post a ready-made code, as long as the op has not shown his attempt here.
> it is more helpful to give hints and tips, so that the op has a chance to find a solution by himself.
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Here is the code try this:
According to you it is the most effective method to solve this problem.
https://code.sololearn.com/cE0BVM77prhC/?ref=app
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Orin Cook Because agent will solve the problem of person by their name, that's why it is sorted according to dictionary in alphabetical order. It's in the question.
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Orin Cook Altaibaatar Enkhbat Inside the function, the other_names string is split into a list called names, and your_name is appended to this list. The names list is then sorted in alphabetical order. The variable position is assigned the index of your_name in the sorted names list and that's how it works.
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Orin Cook No worries, happens to the best of us! It's like finding Waldo in a sea of emojis. 😂
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Ah, so it is, missed that on my first reading somehow.
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Yes I got you Lothar ,actually i have a practice of watching solution early by just practicing 2 3 times and understanding the code and algorithm after that, it doesn't waste my time much on a single problem and I can cover more effectively. That's why i send others too.I will take care of that next time. Thanks for suggestion.
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I don't understand what you're trying to do here, especially why you'd sort.
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Altaibaatar Enkhbat I think that math.ceil would not be useful in the problem solution.
Since you asked for an alternative approach, here is a way to solve it without sorting:
1. Take inputs from user
2. Split names into a list
3. Loop through the list and count how many names are alphabetically less than or equal to "my" name. (No sorting.)
4. Calculate wait time
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You do not need use math.ceil method in this simple task("new driver's license "). If you show code, so we can help you with that