Issue with the tuple coding exercise?

Question

Tuple coding exercise issue even with the solution that solo learn provides.

contacts = [

('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]
name= input()

for x in contacts:
if name in x:
print(str(x[0])+" is "+str(x[1]))
break

elif x not in contacts:
print("Not Found")

Answer 1

# Try this code.
# Hint: the else block will not be executed if the loop is stopped by a break statement.

for x in contacts:
if name in x:
print(x)
break
else:
print("Not Found")

Answer 2

It should be

elif name not in x

Basically just "else" statement would do the same

Answer 3

Try this:

x=input()
count=0
for i in contacts:
if i[0]==x:
print (f"{x} is {i[1]}")
count+=1
if count==0:
print ("Not Found")

#as we need to write “Not Found” only once, we can’t print it while looping. Thats why we should print it in another condition “if”:)