How to access Tuples value

Question

Im taking a Sololearn Practice, and Im stumped by this question:

--------------------------------------------------
You are given a list of contacts, where each contact is represented by a tuple, with the name and age of the contact.
Complete the program to get a string as input, search for the name in the list of contacts and output the age of the contact in the format presented below:

Sample Input

John

Sample Output

John is 31

::If the contact is not found, the program should output "Not Found".

------------------------------------------------------------------

I tried it by doing the code below, but when I run it it always say "Not found:"

contacts = [
('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]
cont = dict(contacts)
name = input()

if name in contacts:
print (name + "is" + cont.get(name))

else:
print ("Not Found")

-----------------------------

I've seen others answer on this app but they look so complicated, and as a newbie I thought I could write it in a code I understand. However, Im stumped.

Please tell me what Im doing wrong.

And if there's other ways to make the code work without changing it too much.

Answer 1

@Slick @Wong Hei Ming

Thank you so. Turned out I cant concatenate string with ints. My bad. For anyone wondering, here's the working Code:

contacts = [
('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]
cont = dict(contacts)
name = input()

if name in cont:
print (name + "is" + str(cont.get(name)))

else:
print ("Not Found")

Answer 2

it's because of your if statement. You check the list of tuples for the name and not your created dictionary.

try
if name in cont:
...
...

Answer 3

The variable 'contacts' is a list of tuples. It is not very convenient for searching.
Converting it to a dictionary, is helpful when there are pairs of keys and values, and all the keys are unique. It is a different data structure.
Your 'cont' variable looks like this (compare with the tuple!):

cont = {
'James': 42,
'Amy': 24, ...
}

So you can easily look up the value (age) that is associated to the key (age).

Answer 4

Jade Tito
you can do the lookup without the need to convert to dict.

contacts = [
('James', 42),
('Amy', 24),
('John', 31),
('Amanda', 63),
('Bob', 18)
]
name = input()

for t in contacts:
if name==t[0]:
print (f"{t[0]} is {t[1]}")
break
else:
print ("Not Found")

Answer 5

Accessing elements inside a tuple is the same as working with a list.
Use the index.

Answer 6

Actually your code works with small modification.
If you look at the error message, it says something like this:
TypeError: can only concatenate str (not "int") to str

It hints there is an integer in somewhere.
Once you figure out where / what is it and convert it into a string...

However this exercise is about tuple, I would not recommend changing the given code.