Can you explain this?

Question

Print(int('0011', 2))
Why it prints 3 as output..
As I thought it will cause an error😐

Answer 1

Code Shooter ,

The second argument to int() is the number base that it should assume when reading the first argument. Base 2 means binary, and 0011 binary is 3 decimal, so int() returned 3, which print() then printed.

What error were you expecting?

Answer 2

You can find the explanation of the int() function in Python documentation.
https://docs.python.org/3/library/functions.html#int
As Rain said, your code converts the binary string to a decimal number.

Answer 3

The second argument is the base.
I suggest you read about number bases.

https://en.m.wikiversity.org/wiki/Number_bases

int('0011', 2)
means base 2 (binary), so it is interpreted as
0*8 + 0*4 + 1*2 + 1*1 = 3

int('0011', 3)
means base 3 (ternary), calculation:
0*27 + 0*9 + 1*3 + 1*1 = 4

int('0011', 10)
in base 10 (decimal):
0*1000 + 0*100 + 1*10 + 1*1 = 11

Hope that makes sense ;)

Answer 4

Thanks!
but if second argument takes binary..
Then check this code also and explain
Print((int('0011', 3))
Why it prints 4 as result..